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carpet -- Ideal of the unique Gorenstein double structure on a 2-dimensional scroll

Synopsis

Description

The routine carpet(a1,a2,m) sets a = min(a1,a2), b = max(a1,a2), and forms two matrices from m: X:the 2 x a matrix that is the first a cols of m; Y:the 2 x b matrix that is the nex b cols of m–that is, cols a1..a1+a2-1 of m; Let Ix, Iy be the ideals of 2 x 2 minors of X and Y. If $a,b\geq 2$,the routine returns Ix+Iy+Imixed, where Imixed consists of the quadrics "outside minor - inside minor", that is, $det(X_{\{i\}},Y_{\{j+1\}})-det(X_{\{i+1\}}|Y_{\{j\}})$, for each pair of (i,i+1), (j,j+1) in the ranges a1 and a2.

If m is usual ideal of the scroll of type (a,b), then carpet(a,b,m) produces the same ideal (over a different ring) as carpet(a,b). This is the ideal of the 2-dimensional rational normal scroll Scroll(a1,a2) is the ideal of 2 x 2 minors of X|Y. The ideal I to be constructed is the ideal of the unique (numerically) K3 scheme that is a double structure on the scroll S(a1,a2).

When a,b > 1, the carpet ideal I is the sum $Ix+Iy$ plus the ideal Imixed

When a = b = 1, I is the square of the determinant of X|Y.

When a = 1, b>1 (or symmetrically), I is defined as in the case a,b>1, after replacing $$ X = \begin{pmatrix} x_0 \\ x_1 \end{pmatrix} $$

by the 2 x 2 matrix $$ \begin{pmatrix} x_0^2 & x_0*x_1 \\ x_0*x_1 & x_1^2 \end{pmatrix} $$ and changing $a$ to 2.

i1 : betti res carpet(2,5)

            0  1  2  3  4  5 6
o1 = total: 1 15 49 70 49 15 1
         0: 1  .  .  .  .  . .
         1: . 15 35 35 14  . .
         2: .  . 14 35 35 15 .
         3: .  .  .  .  .  . 1

o1 : BettiTally
i2 : S = ZZ/101[a..j]

o2 = S

o2 : PolynomialRing
i3 : m = genericMatrix(S,a,2,5)

o3 = | a c e g i |
     | b d f h j |

             2      5
o3 : Matrix S  <-- S
i4 : I = carpet(2,3,m)

o4 = ideal (b*c - a*d, b*e - a*f, d*e - c*f, d*g - c*h - b*i + a*j, f*g - e*h
     ------------------------------------------------------------------------
     - d*i + c*j, h*i - g*j)

o4 : Ideal of S
i5 : L = primaryDecomposition I;
i6 : betti res L_0

            0  1  2  3 4
o6 = total: 1 10 20 15 4
         0: 1  .  .  . .
         1: . 10 20 15 4

o6 : BettiTally
i7 : betti res L_1

            0  1  2  3  4 5
o7 = total: 1 15 40 45 24 5
         0: 1  .  .  .  . .
         1: . 15 40 45 24 5

o7 : BettiTally

Caveat

We require $a1,a2 \ge 1$. If $a1>a2$ then the blocks are reversed, so that the smaller block always comes first. The script generalizeScroll is a more general tool that can do the same things.

See also

Ways to use carpet:

For the programmer

The object carpet is a method function with options.