map(LieAlgebra) -- get the map of a minimal model

Function: map
Usage:

f = map(M)
Inputs:
- M, an instance of the type LieAlgebra, the minimal model
Optional inputs:
- Degree => ..., default value null,
- DegreeLift => ..., default value null,
- DegreeMap => ..., default value null,
Outputs:
- f, an instance of the type LieAlgebraMap,

Description

The optional inputs given above are not relevant for Lie algebras. If $M$ is the minimal model of a Lie algebra $L$, then there is defined a Lie algebra map $f: M \ \to\ L$, and this map is represented by map(M).

i1 : L=lieAlgebra{a,b,c}/{a b,a b c}

o1 = L

o1 : LieAlgebra

i2 : M=minimalModel(3,L)

o2 = M

o2 : LieAlgebra

i3 : describe map(M)

o3 = fr  => a
       0
     fr  => b
       1
     fr  => c
       2
     fr  => 0
       3
     fr  => 0
       4
     source => M
     target => L

Ways to use this method:

map(LieAlgebra) -- get the map of a minimal model

The source of this document is in GradedLieAlgebras/doc.m2:982:0.

map(LieAlgebra) -- get the map of a minimal model

Description

See also

Ways to use this method: